Optimal. Leaf size=376 \[ \frac {8 a^{5/4} c^{3/4} \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (25 \sqrt {a} B+63 A \sqrt {c}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{105 e^3 \sqrt {e x} \sqrt {a+c x^2}}-\frac {48 a^{5/4} A c^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 e^3 \sqrt {e x} \sqrt {a+c x^2}}-\frac {8 a c \sqrt {a+c x^2} (63 A-25 B x)}{105 e^3 \sqrt {e x}}-\frac {4 \left (a+c x^2\right )^{3/2} (25 a B-21 A c x)}{105 e^2 (e x)^{3/2}}-\frac {2 \left (a+c x^2\right )^{5/2} (7 A-5 B x)}{35 e (e x)^{5/2}}+\frac {48 a A c^{3/2} x \sqrt {a+c x^2}}{5 e^3 \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )} \]
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Rubi [A] time = 0.41, antiderivative size = 376, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {813, 842, 840, 1198, 220, 1196} \[ \frac {8 a^{5/4} c^{3/4} \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (25 \sqrt {a} B+63 A \sqrt {c}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{105 e^3 \sqrt {e x} \sqrt {a+c x^2}}-\frac {48 a^{5/4} A c^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 e^3 \sqrt {e x} \sqrt {a+c x^2}}-\frac {4 \left (a+c x^2\right )^{3/2} (25 a B-21 A c x)}{105 e^2 (e x)^{3/2}}-\frac {8 a c \sqrt {a+c x^2} (63 A-25 B x)}{105 e^3 \sqrt {e x}}-\frac {2 \left (a+c x^2\right )^{5/2} (7 A-5 B x)}{35 e (e x)^{5/2}}+\frac {48 a A c^{3/2} x \sqrt {a+c x^2}}{5 e^3 \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )} \]
Antiderivative was successfully verified.
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Rule 220
Rule 813
Rule 840
Rule 842
Rule 1196
Rule 1198
Rubi steps
\begin {align*} \int \frac {(A+B x) \left (a+c x^2\right )^{5/2}}{(e x)^{7/2}} \, dx &=-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}-\frac {2 \int \frac {(-5 a B e-7 A c e x) \left (a+c x^2\right )^{3/2}}{(e x)^{5/2}} \, dx}{7 e^2}\\ &=-\frac {4 (25 a B-21 A c x) \left (a+c x^2\right )^{3/2}}{105 e^2 (e x)^{3/2}}-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}+\frac {4 \int \frac {\left (21 a A c e^2+25 a B c e^2 x\right ) \sqrt {a+c x^2}}{(e x)^{3/2}} \, dx}{35 e^4}\\ &=-\frac {8 a c (63 A-25 B x) \sqrt {a+c x^2}}{105 e^3 \sqrt {e x}}-\frac {4 (25 a B-21 A c x) \left (a+c x^2\right )^{3/2}}{105 e^2 (e x)^{3/2}}-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}-\frac {8 \int \frac {-25 a^2 B c e^3-63 a A c^2 e^3 x}{\sqrt {e x} \sqrt {a+c x^2}} \, dx}{105 e^6}\\ &=-\frac {8 a c (63 A-25 B x) \sqrt {a+c x^2}}{105 e^3 \sqrt {e x}}-\frac {4 (25 a B-21 A c x) \left (a+c x^2\right )^{3/2}}{105 e^2 (e x)^{3/2}}-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}-\frac {\left (8 \sqrt {x}\right ) \int \frac {-25 a^2 B c e^3-63 a A c^2 e^3 x}{\sqrt {x} \sqrt {a+c x^2}} \, dx}{105 e^6 \sqrt {e x}}\\ &=-\frac {8 a c (63 A-25 B x) \sqrt {a+c x^2}}{105 e^3 \sqrt {e x}}-\frac {4 (25 a B-21 A c x) \left (a+c x^2\right )^{3/2}}{105 e^2 (e x)^{3/2}}-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}-\frac {\left (16 \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {-25 a^2 B c e^3-63 a A c^2 e^3 x^2}{\sqrt {a+c x^4}} \, dx,x,\sqrt {x}\right )}{105 e^6 \sqrt {e x}}\\ &=-\frac {8 a c (63 A-25 B x) \sqrt {a+c x^2}}{105 e^3 \sqrt {e x}}-\frac {4 (25 a B-21 A c x) \left (a+c x^2\right )^{3/2}}{105 e^2 (e x)^{3/2}}-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}+\frac {\left (16 a^{3/2} \left (25 \sqrt {a} B+63 A \sqrt {c}\right ) c \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+c x^4}} \, dx,x,\sqrt {x}\right )}{105 e^3 \sqrt {e x}}-\frac {\left (48 a^{3/2} A c^{3/2} \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx,x,\sqrt {x}\right )}{5 e^3 \sqrt {e x}}\\ &=-\frac {8 a c (63 A-25 B x) \sqrt {a+c x^2}}{105 e^3 \sqrt {e x}}+\frac {48 a A c^{3/2} x \sqrt {a+c x^2}}{5 e^3 \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )}-\frac {4 (25 a B-21 A c x) \left (a+c x^2\right )^{3/2}}{105 e^2 (e x)^{3/2}}-\frac {2 (7 A-5 B x) \left (a+c x^2\right )^{5/2}}{35 e (e x)^{5/2}}-\frac {48 a^{5/4} A c^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 e^3 \sqrt {e x} \sqrt {a+c x^2}}+\frac {8 a^{5/4} \left (25 \sqrt {a} B+63 A \sqrt {c}\right ) c^{3/4} \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{105 e^3 \sqrt {e x} \sqrt {a+c x^2}}\\ \end {align*}
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Mathematica [C] time = 0.03, size = 86, normalized size = 0.23 \[ -\frac {2 a^2 x \sqrt {a+c x^2} \left (3 A \, _2F_1\left (-\frac {5}{2},-\frac {5}{4};-\frac {1}{4};-\frac {c x^2}{a}\right )+5 B x \, _2F_1\left (-\frac {5}{2},-\frac {3}{4};\frac {1}{4};-\frac {c x^2}{a}\right )\right )}{15 (e x)^{7/2} \sqrt {\frac {c x^2}{a}+1}} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.01, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (B c^{2} x^{5} + A c^{2} x^{4} + 2 \, B a c x^{3} + 2 \, A a c x^{2} + B a^{2} x + A a^{2}\right )} \sqrt {c x^{2} + a} \sqrt {e x}}{e^{4} x^{4}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (c x^{2} + a\right )}^{\frac {5}{2}} {\left (B x + A\right )}}{\left (e x\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.09, size = 367, normalized size = 0.98 \[ -\frac {2 \left (-15 B \,c^{3} x^{7}-21 A \,c^{3} x^{6}-95 B a \,c^{2} x^{5}+231 A a \,c^{2} x^{4}-504 \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {c x}{\sqrt {-a c}}}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, A \,a^{2} c \,x^{2} \EllipticE \left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )+252 \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {c x}{\sqrt {-a c}}}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, A \,a^{2} c \,x^{2} \EllipticF \left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )-45 B \,a^{2} c \,x^{3}+273 A \,a^{2} c \,x^{2}-100 \sqrt {-a c}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {c x}{\sqrt {-a c}}}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, B \,a^{2} x^{2} \EllipticF \left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )+35 B \,a^{3} x +21 A \,a^{3}\right )}{105 \sqrt {c \,x^{2}+a}\, \sqrt {e x}\, e^{3} x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (c x^{2} + a\right )}^{\frac {5}{2}} {\left (B x + A\right )}}{\left (e x\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (c\,x^2+a\right )}^{5/2}\,\left (A+B\,x\right )}{{\left (e\,x\right )}^{7/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 56.59, size = 314, normalized size = 0.84 \[ \frac {A a^{\frac {5}{2}} \Gamma \left (- \frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{4}, - \frac {1}{2} \\ - \frac {1}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 e^{\frac {7}{2}} x^{\frac {5}{2}} \Gamma \left (- \frac {1}{4}\right )} + \frac {A a^{\frac {3}{2}} c \Gamma \left (- \frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, - \frac {1}{4} \\ \frac {3}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{e^{\frac {7}{2}} \sqrt {x} \Gamma \left (\frac {3}{4}\right )} + \frac {A \sqrt {a} c^{2} x^{\frac {3}{2}} \Gamma \left (\frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {3}{4} \\ \frac {7}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 e^{\frac {7}{2}} \Gamma \left (\frac {7}{4}\right )} + \frac {B a^{\frac {5}{2}} \Gamma \left (- \frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, - \frac {1}{2} \\ \frac {1}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 e^{\frac {7}{2}} x^{\frac {3}{2}} \Gamma \left (\frac {1}{4}\right )} + \frac {B a^{\frac {3}{2}} c \sqrt {x} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{e^{\frac {7}{2}} \Gamma \left (\frac {5}{4}\right )} + \frac {B \sqrt {a} c^{2} x^{\frac {5}{2}} \Gamma \left (\frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{4} \\ \frac {9}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 e^{\frac {7}{2}} \Gamma \left (\frac {9}{4}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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